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 SQL script to automatically distribute utility job

Author  Topic 

rbecl
Starting Member

1 Post

Posted - 2010-08-16 : 05:40:25
Hi,

I would like to write a SQL script to automatically distribute all the utility jobs over a 19:00 to 21:00 time window becuase we moved a lot of databases and, because of the way they were moved, all their utility jobs are now scheduled for 19:45.

These should be spread out between 19:00 and 21:00, so jobs scheduled for 19:45 had to be re-scheduled manually then so that they don’t all happen at once.

So far, I have:

--Check times of existing backup jobs
use MSDB
select [name], next_run_date, next_run_time
from sysjobschedules js left join sysjobs j
on j.job_id = js.job_id
where [name] like '%Utility01%' --and [next_run_time] = 194500
order by next_run_date, next_run_time

-- get the number of jobs

use msdb

DECLARE @count int, @time int, @incrementPeriod int;

SELECT @count =
COUNT(job_id)
from [sysjobschedules] where [next_run_time] between 190000 and 210000

SELECT @count

-- find average space of time period distribution

SET @time = 110;
SET @incrementPeriod = @count/@time
SELECT @incrementPeriod

--

Does anyone have any advice as to how I can distribute the their new times? any help is appreciated
   

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