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SQLforum
Starting Member
4 Posts |
Posted - 2011-01-24 : 16:00:30
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| Dear All, I am trying to create buckets using a string column. This string column contain 12 digits of number from 0-9. ex: 001211121003, 321010987642.Here is my condition:If the "1" show up twice in "DQ_string" then all other digits within the string must be < 1. or If the "2" show up 1 time then all other digits within "DQ_string" must be < 2Please advise. Thanks! |
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tkizer
Almighty SQL Goddess
38200 Posts |
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SQLforum
Starting Member
4 Posts |
Posted - 2011-01-24 : 16:20:29
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| Tara, thanks for your reply but I need to write this up myself. "DQ_tring" is the column name. number in that string indicate its payment strength for 12 months period. "1" meaning 30 late or "2" will be 60 days late etc. I need to find out within that string how many times the 1 or 2 appear but never more than 2 within that string. Can someone help? |
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robvolk
Most Valuable Yak
15732 Posts |
Posted - 2011-01-24 : 17:21:56
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| SELECT CASE WHEN DQ_String LIKE '%2%2%' THEN 'Total Deadbeat'WHEN DQ_String LIKE '%2%' THEN '60 Days Late'WHEN DQ_String LIKE '%1%1%' THEN 'Deadbeat'WHEN DQ_String LIKE '%1%' THEN '30 Days Late'ELSE 'Not Late' END AS PaymentHistoryFROM myTable |
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SQLforum
Starting Member
4 Posts |
Posted - 2011-01-24 : 17:53:04
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| Thanks Robvolk, However I only need to see 1 or 2 twice within that string and the rest of the number in that string will be less than that number. ex: 01100000000, or 010010000000 or 0200010000, or 02000200000 etc. yours giving me 1 or 2 more than twice plus number > 2 or 1. |
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robvolk
Most Valuable Yak
15732 Posts |
Posted - 2011-01-24 : 18:29:34
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| Just remove the WHEN conditions you don't need from the expression.The example I gave doesn't check that the other digits are all zero, but from what you've described it doesn't seem necessary if they meet either of the other conditions. |
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