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Grab Maximum Order Amount

Author

Topic

Vack
Aged Yak Warrior

530 Posts

Posted - 2011-02-01 : 11:53:39

I have the following:


SELECT     dbo.AllOEOrders.*
FROM         dbo.AllOEOrders
WHERE     (CONVERT(varchar(8), entered_dt) = DATEADD([day], DATEDIFF([day], 0, GETDATE()), 0)) AND (ord_type <> 'Q') AND (status <> 'C')

I want to grab the record with the maximum tot_sls_amt

How can I add that to the code above?

SQL 2000

webfred
Master Smack Fu Yak Hacker

8781 Posts

Posted - 2011-02-01 : 11:56:18

quote:
Originally posted by Vack

I have the following:

SELECT top 1 dbo.AllOEOrders.*
FROM dbo.AllOEOrders
WHERE (CONVERT(varchar(8), entered_dt) = DATEADD([day], DATEDIFF([day], 0, GETDATE()), 0)) AND (ord_type <> 'Q') AND (status <> 'C')
order by tot_sls_amt DESC

I want to grab the record with the maximum tot_sls_amt

How can I add that to the code above?

SQL 2000

No, you're never too old to Yak'n'Roll if you're too young to die.

ahmeds08
Aged Yak Warrior

737 Posts

Posted - 2011-02-02 : 00:35:54

if you are finding maximum order for an item then just group by the item.

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