COUNT ALPHABETS - SQL Server Forums

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COUNT ALPHABETS

Author

Topic

pnpsql
Posting Yak Master

246 Posts

Posted - 2012-05-04 : 02:41:56

HI TEAM ,

I NEED TO CHECK THE ALPHABETS IN STRING, THERE IS NO NEED TO COUNT NUMERICALS.PLS HELP

challenge everything

khtan
In (Som, Ni, Yak)

17689 Posts

Posted - 2012-05-04 : 06:15:53

make use of the function here
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=79083&SearchTerms=fnFilterString

KH
[spoiler]Time is always against us[/spoiler]

malpashaa
Constraint Violating Yak Guru

264 Posts

Posted - 2012-05-05 : 14:28:45

Try something like this:


SELECT T.str, SUM(LEN(T.str) - LEN(REPLACE(T.str, C.c, ''))) AS cnt
  FROM YourTable AS T
       CROSS JOIN
       (VALUES('A'), ('B'), ('C'), ('D'), ('E'), ('F'), ('G'),
              ('H'), ('I'), ('J'), ('K'), ('L'), ('M'), ('N'),
              ('O'), ('P'), ('Q'), ('R'), ('S'), ('T'), ('U'),
              ('V'), ('W'), ('X'), ('Y'), ('Z')) AS C(c)
 GROUP BY T.str;

For us, there is only the trying. The rest is not our business. ~T.S. Eliot

Muhammad Al Pasha

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