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replace function

Author

Topic

aakcse
Aged Yak Warrior

570 Posts

Posted - 2012-07-17 : 05:46:36

In a column I want to replace the second occurance of single char '/' with char(32) I,e. space.

How can I do so?

I am able to locate that value but not able to replace I have a function "count_char" to find the number of rec which has '/' more than once


update #table1 set col1= Replace...
where CountChar(lump,'/')>1 

I am able to locate that char by using below string fun

SUBSTRING(col1,charindex('/',col1, CHARINDEX('/',col1,1)+1),1)

-Neil

webfred
Master Smack Fu Yak Hacker

8781 Posts

Posted - 2012-07-17 : 06:44:18

If you are able to locate the position of that char then have a look at STUFF()

No, you're never too old to Yak'n'Roll if you're too young to die.

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2012-07-17 : 09:59:24

see

http://itdeveloperzone.blogspot.com/2012/03/find-nth-occurrence-of-character-sql.html

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

nigelrivett
Master Smack Fu Yak Hacker

3385 Posts

Posted - 2012-07-17 : 13:45:45

No need for the function.
Something like

update #table1
set col1= stuff(col1,charindex('/',col1, CHARINDEX('/',col1,1)+1),1,'')
where len(replace(lump,'/','')+'|') - len(lump+'|') > 1

==========================================
Cursors are useful if you don't know sql.
SSIS can be used in a similar way.
Beer is not cold and it isn't fizzy.

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