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Dan1978
Starting Member
5 Posts |
Posted - 2012-09-11 : 09:25:07
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| Hi,I am trying to create a process to reformat telephone numbers in a table. Below are the main types of errors I'm faced with e.g. letters at the end of the numbers, spaces in middle, mobile numbers missing a leading zero. Would anyone be able to provide some information about the best way to resolve/program the below issue.All help would be much appreciated.Examples of what is in the database and what I would like the output to be.01473 743719 Ray ==> 0147474371901226386486 – clt ==> 0122638648607763 650906 ==> 077636509067894728202 ==> 07894728202 |
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xhostx
Constraint Violating Yak Guru
277 Posts |
Posted - 2012-09-11 : 09:40:50
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| [code]declare @var varchar(40)set @var='78947 28202 lkj'SELECT CASE WHEN SUBSTRING(replace(substring (@var,1, PATINDEX('%[A-Za-z]%',@var)-1),CHAR(32),''),1,1)like '0' THEN replace(substring (@var,1, PATINDEX('%[A-Za-z]%',@var)-1),CHAR(32),'') when SUBSTRING (replace(substring (@var,1, PATINDEX('%[A-Za-z]%',@var)-1),CHAR(32),''),1,1) like '%[1-9]%' then '0'+replace(substring (@var,1, PATINDEX('%[A-Za-z]%',@var)-1),CHAR(32),'') end[/code]this case has all exception.--------------------------Joins are what RDBMS's do for a living |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2012-09-11 : 11:01:19
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| [code]SELECT LEFT(REPLACE(field,' ',''),CASE WHEN PATINDEX('%[^0-9]%',REPLACE(field,' ',''))=0 THEN LEN(REPLACE(field,' ','')) ELSE PATINDEX('%[^0-9]%',REPLACE(field,' ',''))-1 END)FROM table[/code]------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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Dan1978
Starting Member
5 Posts |
Posted - 2012-09-11 : 11:15:01
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| Thank you for your help |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2012-09-11 : 11:28:00
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| wc------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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