ANSI OUTER JOIN RECORD COUNT VARIATION

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ANSI OUTER JOIN RECORD COUNT VARIATION

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Topic

raguyazhin
Posting Yak Master

105 Posts

Posted - 2012-11-03 : 02:21:12

Hi,

I am Planning to convert the T-SQL Joins to ANSI Joins But the one of the below query having variation of record counts.kindly suggest me what are the problems in the below queries.

--T-SQL Join Query--

SELECT * FROM
dbo.CL_CLINICAL_MASTER SPM,
dbo.CL_ITEM_STOCK_MASTER BID,
dbo.CL_ITEM_MASTER IM,
dbo.CL_ITEM_CATEGORY UM
WHERE
SPM.CCM_CLINICAL_CD*= BID.CIS_CLINICAL_CD
AND IM.CIM_ITEM_CODE*= BID.CIS_ITEM_CD
AND IM.CIM_ITEM_CATEGORY_CD= UM.CIC_CATEGORY_CD

--5991 records return

--ANSI Join Query--

SELECT * FROM
CL_CLINICAL_MASTER AS SPM LEFT OUTER JOIN
CL_ITEM_STOCK_MASTER AS BID ON SPM.CCM_CLINICAL_CD = BID.CIS_CLINICAL_CD RIGHT OUTER JOIN
CL_ITEM_MASTER AS IM ON BID.CIS_ITEM_CD = IM.CIM_ITEM_CODE INNER JOIN
CL_ITEM_CATEGORY AS UM ON IM.CIM_ITEM_CATEGORY_CD = UM.CIC_CATEGORY_CD

--4684 records return

How do i match the ANSI Join Query to T-SQL Join Query.

--
Ragu

nigelrivett
Master Smack Fu Yak Hacker

3385 Posts

Posted - 2012-11-03 : 10:55:13

how about

SELECT * FROM
CL_CLINICAL_MASTER AS SPM
cross join CL_ITEM_MASTER AS IM
join CL_ITEM_CATEGORY AS UM
on IM.CIM_ITEM_CATEGORY_CD = UM.CIC_CATEGORY_CD
LEFT JOIN CL_ITEM_STOCK_MASTER AS BID
ON SPM.CCM_CLINICAL_CD = BID.CIS_CLINICAL_CD
and IM.CIM_ITEM_CODE = BID.CIS_ITEM_CD

==========================================
Cursors are useful if you don't know sql.
SSIS can be used in a similar way.
Beer is not cold and it isn't fizzy.

Ifor
Aged Yak Warrior

700 Posts

Posted - 2012-11-05 : 06:59:43

or maybe:


SELECT *
FROM dbo.CL_CLINICAL_MASTER SPM
	LEFT JOIN dbo.CL_ITEM_STOCK_MASTER BID
		ON SPM.CCM_CLINICAL_CD = BID.CIS_CLINICAL_CD
	RIGHT JOIN
	(
		dbo.CL_ITEM_MASTER IM
		JOIN dbo.CL_ITEM_CATEGORY UM
			ON IM.CIM_ITEM_CATEGORY_CD = UM.CIC_CATEGORY_CD
	)
		ON BID.CIS_ITEM_CD = IM.CIM_ITEM_CODE

The thing to remember with the *=/=* syntax is that the * is against the table where all the rows are preserved.

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