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Ally
Starting Member
10 Posts |
Posted - 2011-05-16 : 13:55:11
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| Hello How can I get the rows count if Recommendation_code = "REC_REV" after the firs REC_REV record?Bu i need to count only 1 time if they comes each other. I should get count of 6 from below table.Thanks for any help credit_application_id app_date Type Recommendation_code login222147 2011-01-19 18:03:24.000 S REC_REV admin 222147 2011-01-19 18:03:24.000 D DECL willis4 222147 2011-02-07 15:23:44.000 S REC_REV admin 222147 2011-02-08 17:32:10.000 S REC_REV admin 222147 2011-02-08 17:32:10.000 D REC_DECL willis4 222147 2011-02-08 17:32:10.000 D DECL yorkb 222147 2011-03-05 11:16:56.000 S REC_REV admin 222147 2011-03-08 10:17:59.000 S REC_REV admin 222147 2011-03-08 10:17:59.000 S REC_REV admin 222147 2011-03-08 10:17:59.000 D REC_DECL levanm4 222147 2011-03-08 10:17:59.000 D REC_DECL levanm4 222147 2011-03-08 10:17:59.000 D DECL chowd6 222147 2011-03-08 10:17:59.000 D DECL chowd6 222147 2011-03-10 09:34:51.000 S REC_REV admin 222147 2011-03-10 09:34:51.000 D DECL simonj4 222147 2011-03-10 17:08:31.000 S REC_REV admin 222147 2011-03-11 15:26:11.000 S REC_REV admin 222147 2011-03-11 15:26:11.000 D DECL simonj4 222147 2011-03-22 13:30:00.000 S REC_REV admin 222147 2011-03-22 13:30:00.000 D REC_DECL simonj4 222147 2011-03-22 13:30:00.000 D APPR yorkb 222147 2011-03-22 13:30:00.000 D DECL admin 222147 2011-03-29 11:55:37.000 S REC_REV admin 222147 2011-03-29 11:55:37.000 D REC_APP mawany 222147 2011-03-29 11:55:37.000 D APPR Yorkb |
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nigelrivett
Master Smack Fu Yak Hacker
3385 Posts |
Posted - 2011-05-16 : 14:03:35
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| You need something to order by and there doesn't seem to be anything here you have three rows with date 20110305 17:32:10 - what order are they in?==========================================Cursors are useful if you don't know sql.SSIS can be used in a similar way.Beer is not cold and it isn't fizzy. |
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Ally
Starting Member
10 Posts |
Posted - 2011-05-16 : 14:17:13
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quote: Originally posted by nigelrivett You need something to order by and there doesn't seem to be anything here you have three rows with date 20110305 17:32:10 - what order are they in?==========================================Cursors are useful if you don't know sql.SSIS can be used in a similar way.Beer is not cold and it isn't fizzy.
It is ordered by App_dateit doesn't look good but there are 5 rows Here are they (, separated now)I dont know how to use cursor :( credit_application_id,app_date,Type,Recommendation_code,login222147,2011-01-19 18:03:24.000,S,REC_REV,admin 222147,2011-01-19 18:03:24.000,D,DECL,willis4 222147,2011-02-07 15:23:44.000,S,REC_REV,admin 222147,2011-02-08 17:32:10.000,S,REC_REV,admin 222147,2011-02-08 17:32:10.000,D,REC_DECL,willis4 222147,2011-02-08 17:32:10.000,D,DECL, yorkb 222147,2011-03-05 11:16:56.000,S,REC_REV,admin 222147,2011-03-08 10:17:59.000,S,REC_REV,admin 222147,2011-03-08 10:17:59.000,S,REC_REV,admin 222147,2011-03-08 10:17:59.000,D,REC_DECL,levanm4 222147,2011-03-08 10:17:59.000,D,REC_DECL,levanm4 222147,2011-03-08 10:17:59.000,D,DECL, chowd6 222147,2011-03-08 10:17:59.000,D,DECL, chowd6 222147,2011-03-10 09:34:51.000,S,REC_REV,admin 222147,2011-03-10 09:34:51.000,D,DECL, simonj4 222147,2011-03-10 17:08:31.000,S,REC_REV,admin 222147,2011-03-11 15:26:11.000,S,REC_REV,admin 222147,2011-03-11 15:26:11.000,D,DECL, simonj4 222147,2011-03-22 13:30:00.000,S,REC_REV,admin 222147,2011-03-22 13:30:00.000,D,REC_DECL,simonj4 222147,2011-03-22 13:30:00.000,D,APPR, yorkb 222147,2011-03-22 13:30:00.000,D,DECL, admin 222147,2011-03-29 11:55:37.000,S,REC_REV,admin 222147,2011-03-29 11:55:37.000,D,REC_APP,mawany 222147,2011-03-29 11:55:37.000,D,APPR, Yorkb |
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nigelrivett
Master Smack Fu Yak Hacker
3385 Posts |
Posted - 2011-05-16 : 14:20:58
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| 222147,2011-02-08 17:32:10.000,S,REC_REV,admin 222147,2011-02-08 17:32:10.000,D,REC_DECL,willis4 222147,2011-02-08 17:32:10.000,D,DECL, yorkb These still look like they have the same app date.If you sort that out it could be something likewith cte as(select credit_application_id, Recommendation_code, seq = row_number() over (partition by credit_application_id order by app_date))select credit_application_id, count(*)from cte cwhere Recommendation_code = 'REC_REV'and not exists (select * from cte c2 where c.credit_application_id = c2.credit_application_id and c2.seq = c.seq - 1 and c2.Recommendation_code = 'REC_REV')group by credit_application_id==========================================Cursors are useful if you don't know sql.SSIS can be used in a similar way.Beer is not cold and it isn't fizzy. |
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Ally
Starting Member
10 Posts |
Posted - 2011-05-16 : 14:32:05
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quote: Originally posted by nigelrivett 222147,2011-02-08 17:32:10.000,S,REC_REV,admin 222147,2011-02-08 17:32:10.000,D,REC_DECL,willis4 222147,2011-02-08 17:32:10.000,D,DECL, yorkb These still look like they have the same app date.If you sort that out it could be something likewith cte as(select credit_application_id, Recommendation_code, seq = row_number() over (partition by credit_application_id order by app_date))select credit_application_id, count(*)from cte cwhere Recommendation_code = 'REC_REV'and not exists (select * from cte c2 where c.credit_application_id = c2.credit_application_id and c2.seq = c.seq - 1 and c2.Recommendation_code = 'REC_REV')group by credit_application_id==========================================Cursors are useful if you don't know sql.SSIS can be used in a similar way.Beer is not cold and it isn't fizzy.
Sorry I am new with sql I didnt get the first part.with cte as(select credit_application_id, Recommendation_code, seq = row_number() over (partition by credit_application_id order by app_date))Can you explain it please?ThanksAlly |
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