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Distinct / group by ignorance

Author

Topic

tyrant911
Starting Member

1 Post

Posted - 2011-09-02 : 14:45:56

Hello,

I'm trying to make my data display every order once, this includes customers with multiple purchases that are taking up multiple rows with the same data. Those duplicate addressed I don't want them to show up.

SELECT color, size, Coupon#, FirstName, LastName, Address + ', ' + City+ ', ' + Province+ '. ' + PostalCode+ ' ' + Country AS "Shipping Address"
FROM [Orders]
WHERE FirstName IN (SELECT DISTINCT FirstName
FROM [Orders])
GROUP BY FirstName, LastName, 'Shipping Address';

I know the problem is me, but it has been years since i took a sql class and don't really know where to turn to get my queries checked.

This is being done on MS SQL 2008 R2

visakh16
Very Important crosS Applying yaK Herder

52326 Posts

Posted - 2011-09-02 : 20:29:19

[code]
SELECT <required columns>
FROM
(
SELECT ROW_NUMBER() OVER (PARTITION BY FirstName, LastName ORDER BY Address + ', ' + City+ ', ' + Province+ '. ' + PostalCode+ ' ' + Country) AS Seq
color, size, [Coupon#], FirstName, LastName, Address + ', ' + City+ ', ' + Province+ '. ' + PostalCode+ ' ' + Country AS [Shipping Address]
FROM [Orders]
)t
WHERE Seq=1
[/code]

------------------------------------------------------------------------------------------------------
SQL Server MVP
http://visakhm.blogspot.com/

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