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 Database Normalization Relationship

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groverSaab
Starting Member

3 Posts

Posted - 2012-03-19 : 08:06:12
If a table has FD(functional Dependency) A->B and A is not the candidate key,then which of the following is true:

a;Data is incorrect
b:Table is not in 2NF(seocnd Normal form)
c:Table involves some redundancy
d:None of these


Plz help????
Thanx in advance.....

ff

tkizer
Almighty SQL Goddess

38200 Posts

Posted - 2012-03-19 : 13:13:20
e:We don't answer homework questions here.

Tara Kizer
Microsoft MVP for Windows Server System - SQL Server
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groverSaab
Starting Member

3 Posts

Posted - 2012-03-20 : 11:49:07
i m jst asking for help......!!
if u can then plz .....!!!!!
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X002548
Not Just a Number

15586 Posts

Posted - 2012-03-20 : 13:05:01
OK..which one did YOU pick?



Brett

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X002548
Not Just a Number

15586 Posts

Posted - 2012-03-20 : 13:05:35
OK, more help

http://www.emunix.emich.edu/~khailany/files/Normalization.htm



Brett

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X002548
Not Just a Number

15586 Posts

Posted - 2012-03-20 : 13:07:13
and then there's

http://blog.sqlauthority.com/2009/10/22/sql-server-difference-between-candidate-keys-and-primary-key-2/



Brett

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X002548
Not Just a Number

15586 Posts

Posted - 2012-03-20 : 13:08:50
...and just an assumption that this

A->B

Means

A is realted to B..I'm guessing they mean 1 to many?



Brett

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groverSaab
Starting Member

3 Posts

Posted - 2012-03-20 : 14:13:28
According to me it should be..
b:Table is not in 2NF(second Normal form)

Bt i m nt sure....!!!
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X002548
Not Just a Number

15586 Posts

Posted - 2012-03-20 : 15:05:20
Why do you say that...

Brett

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