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Fill gap in date periods

Author

Topic

Clas
Starting Member

33 Posts

Posted - 2012-08-25 : 05:27:59

Create and fill gap in dateperiod

create table #source
(
individual int,
movingIN date,
movingOut date,
household int
)

Insert INTO #source
SELECT '3','1858-06-27', '1873-10-31','100'
UNION ALL SELECT '3','1877-11-01', '1884-09-05','100'
UNION ALL SELECT '4','1861-04-26', '1875-10-31','100'
UNION ALL SELECT '4','1875-10-31', '1881-11-09','300'
UNION ALL SELECT '4','1881-11-09', '1882-07-01','100'
UNION ALL SELECT '4','1882-11-02', '1883-11-22','400'
UNION ALL SELECT '4','1884-11-22', '1885-05-20','100'

Gap (household -1):

3 1873-10-31 1877-11-01 -1
4 1882-07-01 1882-11-02 -1
4 1883-11-22 1884-11-22 -1

RESULT:
individual movingIN movingOut household
3 1858-06-27 1873-10-31 100
3 1873-10-31 1877-11-01 -1
3 1877-11-01 1884-09-05 100
4 1861-04-26 1875-10-31 100
4 1875-10-31 1881-11-09 300
4 1881-11-09 1882-07-01 100
4 1882-07-01 1882-11-02 -1
4 1882-11-02 1883-11-22 400
4 1883-11-22 1884-11-22 -1
4 1884-11-22 1885-05-20 100

THANKS !

khtan
In (Som, Ni, Yak)

17689 Posts

Posted - 2012-08-25 : 10:03:53

[code]; with cte as
(
select *, rn = row_number() over (partition by individual order by movingIN)
from #source
)
select c1.individual, movingIN = c1.movingOut, movingOut = c2.movingIN, household = -1
from cte c1
inner join cte c2 on c1.individual = c2.individual
and c1.rn = c2.rn - 1
where c1.movingOut <> c2.movingIN

union all

select individual, movingIN, movingOut, household
from cte[/code]

KH
[spoiler]Time is always against us[/spoiler]

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