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gpspreet
Starting Member
8 Posts |
Posted - 2013-03-30 : 00:40:04
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AdventureWorks2012:Identify the customers who have orders with total order value of more than $100,000.00 in the year 2007. Show: customer ID, Customer Name of such ordersOrder by: customer ID |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2013-03-30 : 01:52:49
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Can we see what you tried yet. This is a straightforward assignment question so unless you tried yourself we wont provide any spoonfed answers.We can give a hint though....Lookup for GROUP BY clause in books online------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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gpspreet
Starting Member
8 Posts |
Posted - 2013-03-30 : 03:42:03
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Sure....I tried Below code. I am unaable to print the Customer Names. SELECT SOH.CustomerID, TotalDue= sum(SOH.TotalDue) FROM Sales.SalesOrderHeader SOH Inner JOIN Sales.Customer CUS ON SOH.CustomerID = CUS.CustomerIDLEFT OUTER JOIN Person.BusinessEntityContact BEC ON CUS.PersonID =BEC.PersonID LEFT OUTER JOIN Person.Person PER ON BEC.BusinessEntityID = PER.BusinessEntityID where year(SOH.OrderDate) = '2007' and TotalDue > 100000 group by SOH.CustomerID ORDER BY SOH.CustomerID; |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2013-03-30 : 03:45:27
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you've not listed customernames in select. Then how would it print them. Add Customername field in SELECT and GROUP BY------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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gpspreet
Starting Member
8 Posts |
Posted - 2013-03-30 : 03:56:10
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Thanks For looking into it...It throws the below error for first,second and last nameColumn 'Person.Person.FirstName' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2013-03-30 : 04:01:47
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just give attention to what i suggested previously.To restateAdd name related fields in SELECT and in GROUP BY------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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gpspreet
Starting Member
8 Posts |
Posted - 2013-03-30 : 05:04:34
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I tried but i am not getting it. How can i combine the existing groupby with select...I am not getting it at all.[SELECT SOH.CustomerID, TotalDue= sum(SOH.TotalDue) FROM Sales.SalesOrderHeader SOH Inner JOIN Sales.Customer CUS ON SOH.CustomerID = CUS.CustomerIDLeft Outer JOIN Person.BusinessEntityContact BEC ON CUS.PersonID =BEC.PersonID Left outer JOIN (select p.FirstName,p.LastName, BusinessEntityID from person.person p ) per ON BEC.BusinessEntityID = per.BusinessEntityID where year(SOH.OrderDate) = '2007' and TotalDue > 100000 group by SOH.CustomerID ORDER BY SOH.CustomerID; |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2013-03-30 : 13:05:48
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[code]SELECT SOH.CustomerID,per.LastName,per.firstName, TotalDue= sum(SOH.TotalDue) FROM Sales.SalesOrderHeader SOH Inner JOIN Sales.Customer CUS ON SOH.CustomerID = CUS.CustomerIDLeft Outer JOIN Person.BusinessEntityContact BEC ON CUS.PersonID =BEC.PersonID Left outer JOIN (select p.FirstName,p.LastName, BusinessEntityID from person.person p ) per ON BEC.BusinessEntityID = per.BusinessEntityID where year(SOH.OrderDate) = '2007' and TotalDue > 100000 group by SOH.CustomerID,per.LastName,per.firstName ORDER BY SOH.CustomerID;[/code]------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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gpspreet
Starting Member
8 Posts |
Posted - 2013-03-31 : 01:38:09
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Its not working... All Name columns gives Null Values. |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2013-03-31 : 02:56:43
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quote: Originally posted by gpspreet Its not working... All Name columns gives Null Values.
That means you dont have any matching records coming in person table. Check is BusinessEntityID values in person table are correct.------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |
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gpspreet
Starting Member
8 Posts |
Posted - 2013-03-31 : 23:57:47
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Ohhh.... Yes, It worked now..SELECT SOH.CustomerID,per.FirstName + ' ' + Per.LastName AS PersonName, TotalDue= sum(SOH.TotalDue) FROM Sales.SalesOrderHeader SOH Inner JOIN Sales.Customer CUS ON SOH.CustomerID = CUS.CustomerIDLeft Outer JOIN Person.BusinessEntityContact BEC ON CUS.PersonID =BEC.PersonID Left outer JOIN (select p.FirstName,p.MiddleName, p.LastName, BusinessEntityID from person.person p ) per ON per.BusinessEntityID = BEC.PersonID where year(SOH.OrderDate) = '2007' and TotalDue > 100000 group by SOH.CustomerID,per.LastName,per.firstName ORDER BY SOH.CustomerID;Change is per.BusinessEntityID = BEC.PersonID instead of BEC.BusinessEntityID..Thanks, for Helping me through out. |
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visakh16
Very Important crosS Applying yaK Herder
52326 Posts |
Posted - 2013-04-01 : 00:26:15
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welcome------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/https://www.facebook.com/VmBlogs |
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