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                                         kieran5405 
                                        Yak Posting Veteran 
                                         
                                        
                                        96 Posts  | 
                                        
                                        
                                            
                                            
                                             Posted - 2014-07-23 : 07:06:02
                                            
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                                            | Hi,I have the below select statement (simplified) - with a Left Join which pulls back a currency amount for the rows.But I have now discovered that in some cases there may be rows duplicated in the database (based on 'asset' field) but this is how it is supposed to be.  As a result I am trying to figure out a way of only assigning one currency amount per duplicated row and a zero amount for the extra duplications.  So, currently with the below SQL, the asset 'Asset25' is returned twice and therefore summed as a total value of €10 (i.e. €5 + €5) when its value is really €5.How could I fix this?Thanks for any help...SELECT b.amount, * FROM database1 a LEFT JOIN database2 b on b.asset_id  = a.asset | 
                                             
                                         
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                                     madhivanan 
                                    Premature Yak Congratulator 
                                     
                                    
                                    22864 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2014-07-23 : 08:14:06
                                          
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                                          | Something like this may workselect case when sno=1 then amount else 0 end as amount, t.othercolumns from(SELECT row_number() over (partition by a.asset order by a.asset) as s_no,b.amount, * FROM database1 a LEFT JOIN database2 b on b.asset_id = a.asset) as tMadhivananFailing to plan is Planning to fail  | 
                                         
                                        
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                                     kieran5405 
                                    Yak Posting Veteran 
                                     
                                    
                                    96 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2014-07-23 : 08:29:30
                                          
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                                          | amazing work...thanks for that...would have never been able to put it together like that.  | 
                                         
                                        
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