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shajimanjeri
Posting Yak Master
179 Posts |
Posted - 2006-10-28 : 02:20:45
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Dear all,I am doing a project on SQL. So I need some help on it...Here I want to get the records from my database by date and time wise.So there is one table with a field name Msg_Time (Type is date&time).Here how to fetch Today's records in between 00:00 to 01:00, 01:00 to 02:00, 02:00 to 03:00, 03:00 to 04:00 etc till 23:00 to 00:00.Here the storing format of date in my table is like "10/28/2006 12:00:00 AM" and "10/28/2006 11:10:00 PM" |
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2006-10-28 : 03:40:28
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for 00:00 to 01:00where Msg_Time >= dateadd(day, datediff(day, 0, getdate()), 0)and Msg_Time < dateadd(hour, 1, dateadd(day, datediff(day, 0, getdate()), 0)) KH |
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shajimanjeri
Posting Yak Master
179 Posts |
Posted - 2006-10-28 : 06:34:54
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Dear khan,Please tell me same way how to find the record from 01:00 to 02:00 and 03:00 to 04:00 etc at the same day.I am new to SQL queriespleasewith regardsshajiquote: Originally posted by khtan for 00:00 to 01:00where Msg_Time >= dateadd(day, datediff(day, 0, getdate()), 0)and Msg_Time < dateadd(hour, 1, dateadd(day, datediff(day, 0, getdate()), 0)) KH
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2006-10-28 : 07:08:12
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You mean generate the hourly time for a day ?select dte = dateadd(hour, hr, dateadd(day, datediff(day, 0, getdate()), 0))from ( select hr = 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 ) d KH |
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shajimanjeri
Posting Yak Master
179 Posts |
Posted - 2006-10-28 : 07:22:35
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Dear KH,No,There is one table with a field name Msg_Time (Type is datetime).and the date format is : "10/28/2006 12:40:00 AM"Here I want to select Today's record on time based.I mean In my database how many messages recieved in time between 00:00 to 01:00, 01:00 to 02:00, 03:00 to 04:00, 05:00 to 06:00 etc till 23:00 to 00:00.How to do this one. Please help me..Regardsshajiquote: Originally posted by khtan You mean generate the hourly time for a day ?select dte = dateadd(hour, hr, dateadd(day, datediff(day, 0, getdate()), 0))from ( select hr = 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 ) d KH
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2006-10-28 : 07:24:18
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Sorry. Don't quite get you. Can you post your table structure, some sample data and the result that you want. KH |
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shajimanjeri
Posting Yak Master
179 Posts |
Posted - 2006-10-28 : 07:40:53
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Dear kh,I have a table with name C1_Messages with three fields (1)ID (2) Messages (3)Msg_Time.Here the end users are sending messages and storing those messages in this table with today's date and time. (once the message is recieved then automatically server date and time will store).Here I am getting 2-20 messages per hour.So here I want to see how many messages recieved on today in between 00:00 to 01:00,and in between 01:00 to 02:00 and in between 02:00 to 03:00, etc till and in between 23:00 to 00:00 (The time are in 24-hour format).How to do thatquote: Originally posted by khtan Sorry. Don't quite get you. Can you post your table structure, some sample data and the result that you want. KH
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SwePeso
Patron Saint of Lost Yaks
30421 Posts |
Posted - 2006-10-28 : 08:01:38
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Please also post in appropriate forum. The Script Library is for posting working scriptselect dateadd(hour, 0, x.hd) FromDateHour, dateadd(second, -1, dateadd(hour, -1, x.hd)) ToDateHour, x.cnt MessagesFROM ( select datediff(hour, 0, Msg_Time) hd, count(*) cnt from mytable where mycolumn >= '20061028' and mycolumn < '20061028' GROUP BY DATEDIFF(hour, 0, Msg_Time) / 24 ) x Peter LarssonHelsingborg, Sweden |
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2006-10-28 : 08:22:37
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[code] where mycolumn >= '20061028' and mycolumn < '20061029'[/code] KH |
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SwePeso
Patron Saint of Lost Yaks
30421 Posts |
Posted - 2006-10-29 : 07:57:53
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How true! I must have been in affect when typing...Peter LarssonHelsingborg, Sweden |
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